Адрес: Тараз 2❤️♞Квалификационный турнир с нормой 4 разряда 19-20.09.2026 Poslední aktualizace20.09.2026 11:54:04, Creator/Last Upload: Kazakhstan Chess Federation (License 6)
Pořadí po 1 kole
| Poř. | St.č. | | Jméno | FED | Rtg | Body | PH 1 | PH 2 | PH 3 |
|---|
| 1 | 1 | | Aidabul, Adi | KAZ | 0 | 1 | 0 | 0 | 1 |
| 2 | 10 | | Kaisarin, Amre | KAZ | 0 | 1 | 0 | 0 | 1 |
| 3 | 11 | | Kaisarina, Azina | KAZ | 0 | 1 | 0 | 0 | 1 |
| 4 | 13 | | Kazybek, Amir | KAZ | 0 | 1 | 0 | 0 | 1 |
| 5 | 14 | | Khikmat, Askhat | KAZ | 0 | 1 | 0 | 0 | 1 |
| 6 | 15 | | Makanalin, Akbar | KAZ | 0 | 1 | 0 | 0 | 1 |
| 7 | 16 | | Medetbek, Kalima | KAZ | 0 | 1 | 0 | 0 | 1 |
| 8 | 17 | | Narbek, Aisultan | KAZ | 0 | 1 | 0 | 0 | 1 |
| 9 | 18 | | Orazbay, Kaisar | KAZ | 0 | 1 | 0 | 0 | 1 |
| 10 | 19 | | Sabitov, Amirhan | KAZ | 0 | 1 | 0 | 0 | 1 |
| 11 | 20 | | Sadykov, Zhandos | KAZ | 0 | 1 | 0 | 0 | 1 |
| 12 | 21 | | Serik, Ailana | KAZ | 0 | 1 | 0 | 0 | 1 |
| 13 | 22 | | Sultanbekov, Daniyar | KAZ | 0 | 1 | 0 | 0 | 1 |
| 14 | 23 | | Tolepbergen, Dinmukhamed | KAZ | 0 | 1 | 0 | 0 | 1 |
| 15 | 26 | | Zhakelovа, Adina | KAZ | 0 | 1 | 0 | 0 | 1 |
| 16 | 2 | | Almira, Kurmangalieva | KAZ | 0 | 0 | 0 | 1 | 0 |
| 17 | 3 | | Amangeldy, Aizere | KAZ | 0 | 0 | 0 | 1 | 0 |
| 18 | 4 | | Askarbek, Daria | KAZ | 0 | 0 | 0 | 1 | 0 |
| 19 | 5 | | Assylbek, Amila | KAZ | 0 | 0 | 0 | 1 | 0 |
| 20 | 6 | | BEKMAGAMBET, IBRAGIM | KAZ | 0 | 0 | 0 | 1 | 0 |
| 21 | 7 | | DABYR, ZHANSULTAN | KAZ | 0 | 0 | 0 | 1 | 0 |
| 22 | 8 | | Issakanova, Adel | KAZ | 0 | 0 | 0 | 1 | 0 |
| 23 | 9 | | Kadylbek, Estay | KAZ | 0 | 0 | 0 | 1 | 0 |
| 24 | 12 | | Kaiyrzhanov, Aziz | KAZ | 0 | 0 | 0 | 1 | 0 |
| 25 | 24 | | Yerzhanov, Medet | KAZ | 0 | 0 | 0 | 1 | 0 |
| 26 | 25 | | Zhakelov, Daniyal | KAZ | 0 | 0 | 0 | 1 | 0 |
| 27 | 27 | | Zhanbolat, Adisha | KAZ | 0 | 0 | 0 | 1 | 0 |
| 28 | 28 | | Zhanbolat, Nurgisa | KAZ | 0 | 0 | 0 | 1 | 0 |
| 29 | 29 | | Zhumabay, Alikhan | KAZ | 0 | 0 | 0 | 1 | 0 |
Poznámka:
Pomocné hodnocení1: Direct Encounter (The results of the players in the same point group)
Pomocné hodnocení2: Buchholz Tie-Breaks (variabel with parameter)
Pomocné hodnocení3: Fide Tie-Break
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